【Python 学习】通过while循环和for循环猜测年龄
发布于2019-08-07 18:22 阅读(867) 评论(0) 点赞(4) 收藏(5)
Python中可以通过while和for循环来限制猜测年龄的次数
1. 在猜测年龄的小程序中，不加循环的代码是这样的：
age_of_yu = 23
guess_age = int(input("guess_age:"))
if guess_age == age_of_yu:
print("you got it!")
elif guess_age > age_of_yu:
print("think smaller...")
else:
print("think bigger...")
# 这里的 int(input("guess_age:")) 是将变量定义的默认数据类型（str）强制转换成 int 类型，从而可以进行 if 的条件比较
2. 通过for循环限制猜测年龄的次数为3次
age_of_yu = 23
for i in range(3):
guess_age = int(input("guess_age:"))
if guess_age == age_of_yu:
print("you got it!")
break
elif guess_age > age_of_yu:
print("think smaller...")
else:
print("think bigger...")
else:
print("you have tried too many times!")
3. 通过 while 循环限制猜测年龄的次数为3次
age_of_yu = 23
count = 0
while count < 3:
guess_age = int(input("guess_age:"))
if guess_age == age_of_yu:
print("you got it!")
break
elif guess_age > age_of_yu:
print("think smaller...")
else:
print("think bigger...")
count += 1
else:
print("you have tried too many times!")
4. 猜测年龄，要求猜到三次询问是否还要继续猜测，如果输入"n"则表示继续猜，否则表示不继续
age_of_yu = 23
count = 0
while count < 3:
guess_age = int(input("guess_age:"))
if guess_age == age_of_yu:
print("you got it!")
break
elif guess_age > age_of_yu:
print("think smaller...")
else:
print("think bigger...")
count += 1
if count == 3:
continue_guess = input("Do you want to go on guessing ?(输入n结束，输入其他任意键继续...)")
if continue_guess != 'n':
count = 0
else:
print("guessing end...")
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作者：急流勇退
链接：https://www.pythonheidong.com/blog/article/12053/6192575784a72a043301/
来源：python黑洞网
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