发布于2019-10-07 09:53 阅读(1860) 评论(0) 点赞(13) 收藏(2)
如果我使用多个列来显示子图,如何动态地向子图串中添加新图?这为一栏回答了这个问题,但我似乎无法修改那里的答案以使其动态添加到具有x
栏的子图中
我修改了Sadarthrion的答案,并尝试了以下操作。在这里,为了举例说明,我制作了number_of_subplots=11
和num_cols = 3
。
import matplotlib.pyplot as plt
def plotSubplots(number_of_subplots,num_cols):
# Start with one
fig = plt.figure()
ax = fig.add_subplot(111)
ax.plot([1,2,3])
for j in range(number_of_subplots):
if j > 0:
# Now later you get a new subplot; change the geometry of the existing
n = len(fig.axes)
for i in range(n):
fig.axes[i].change_geometry(n+1, num_cols, i+1)
# Add the new
ax = fig.add_subplot(n+1, 1, n+1)
ax.plot([4,5,6])
plt.show()
plotSubplots(11,3)
如您所见,这没有给我我想要的东西。第一个图占用了所有列,其他图小于它们应该的大小。
编辑:
('2.7.6 | 64-bit | (default, Sep 15 2014, 17:36:35) [MSC v.1500 64 bit (AMD64)]'
我也有matplotlib版本1.4.3:
import matplotlib as mpl
print mpl.__version__
1.4.3
我在下面尝试了Paul的答案,并收到以下错误消息:
import math
import matplotlib.pyplot as plt
from matplotlib import gridspec
def do_plot(ax):
ax.plot([1,2,3], [4,5,6], 'k.')
N = 11
cols = 3
rows = math.ceil(N / cols)
gs = gridspec.GridSpec(rows, cols)
fig = plt.figure()
for n in range(N):
ax = fig.add_subplot(gs[n])
do_plot(ax)
fig.tight_layout()
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-1-f74203b1c1bf> in <module>()
15 fig = plt.figure()
16 for n in range(N):
---> 17 ax = fig.add_subplot(gs[n])
18 do_plot(ax)
19
C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\figure.pyc in add_subplot(self, *args, **kwargs)
962 self._axstack.remove(ax)
963
--> 964 a = subplot_class_factory(projection_class)(self, *args, **kwargs)
965
966 self._axstack.add(key, a)
C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\axes\_subplots.pyc in __init__(self, fig, *args, **kwargs)
73 raise ValueError('Illegal argument(s) to subplot: %s' % (args,))
74
---> 75 self.update_params()
76
77 # _axes_class is set in the subplot_class_factory
C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\axes\_subplots.pyc in update_params(self)
113 self.figbox, self.rowNum, self.colNum, self.numRows, self.numCols = 114 self.get_subplotspec().get_position(self.figure,
--> 115 return_all=True)
116
117 def is_first_col(self):
C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\gridspec.pyc in get_position(self, fig, return_all)
423
424 figBottoms, figTops, figLefts, figRights = --> 425 gridspec.get_grid_positions(fig)
426
427
C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\gridspec.pyc in get_grid_positions(self, fig)
103 cellHeights = [netHeight*r/tr for r in self._row_height_ratios]
104 else:
--> 105 cellHeights = [cellH] * nrows
106
107 sepHeights = [0] + ([sepH] * (nrows-1))
TypeError: can't multiply sequence by non-int of type 'float'
假设您知道网格的至少一维和总图数,我将使用该gridspec
模块和一些数学知识。
import math
import matplotlib.pyplot as plt
from matplotlib import gridspec
def do_plot(ax):
ax.plot([1,2,3], [4,5,6], 'k.')
N = 11
cols = 3
rows = int(math.ceil(N / cols))
gs = gridspec.GridSpec(rows, cols)
fig = plt.figure()
for n in range(N):
ax = fig.add_subplot(gs[n])
do_plot(ax)
fig.tight_layout()
作者:黑洞官方问答小能手
链接:https://www.pythonheidong.com/blog/article/132096/e8d09ac5f26ff7b6dac5/
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