发布于2019-11-17 14:10 阅读(218) 评论(0) 点赞(30) 收藏(1)
每次尝试编码时,它都有效,但是当我键入代码时'stop'
,出现错误:
ValueError:以10为底的int()的无效文字:'stop'
def guessingGame():
global randomNum
guessTry = 3
while True:
guess = input('Guess a Number between 1 - 10, You have 3 Tries, or Enter Stop: ')
if int(guess) == randomNum:
print('Correct')
break
if int(guess) < randomNum:
print('Too Low')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if int(guess) > randomNum:
print('Too High')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if guessTry == 0:
print('You have no more tries')
return
if str(guess) == 'stop' or str(guess) == 'Stop':
break
传递给的字符串int()
应仅包含数字:
>>> int("stop")
Traceback (most recent call last):
File "<ipython-input-114-e5503af2dc1c>", line 1, in <module>
int("stop")
ValueError: invalid literal for int() with base 10: 'stop'
一个快速的解决方案是在此处使用异常处理:
def guessingGame():
global randomNum
global userScore
guessTry = 3
while True:
guess = input('Guess a Number between 1 - 10, You have 3 Tries, or Enter Stop: ')
try:
if int(guess) == randomNum:
print('Correct')
break
if int(guess) < randomNum:
print('Too Low')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if int(guess) > randomNum:
print('Too High')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if guessTry == 0:
print('You have no more tries')
return
except ValueError:
#no need of str() here
if guess.lower() == 'stop':
break
guessingGame()
而且您可以使用guess.lower() == 'stop'
匹配“ stop”的任何大小写组合:
>>> "Stop".lower() == "stop"
True
>>> "SToP".lower() == "stop"
True
>>> "sTOp".lower() == "stop"
True
作者:黑洞官方问答小能手
链接:https://www.pythonheidong.com/blog/article/158213/56de142ecdea1f691341/
来源:python黑洞网
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