发布于2019-08-10 07:10 阅读(234) 评论(0) 点赞(1) 收藏(4)
Django中利用js来操作数据的常规操作一般为点(.)操作符来获取字典或列表的数据,一般如{{data.0}},{{data.arg}}
但有时如果数据是嵌套类型的数据时,直接获取某个值就变得困难了,比如下面的格式要获取
correct中qxl的值
startArgsSet={"correct":{"qxl":0,"kkx":0},"reliable":{"qxl":0,"kkx":0},"security":{"qxl":0,"kkx":0},"understand":{"qxl":0,"kkx":0},"entropy":{"qxl":0,"kkx":0}, "mature":{"qxl":0,"kkx":0},"active":{"qxl":0,"kkx":0},"service":{"qxl":0,"kkx":0},"file":{"qxl":0,"kkx":0}, "tech":{"qxl":0,"kkx":0},"property":{"qxl":0,"kkx":0},"organize":{"qxl":0,"kkx":0},"develop":{"qxl":0,"kkx":0}, "source":{"qxl":0,"kkx":0},"update":{"qxl":0,"kkx":0},"fix":{"qxl":0,"kkx":0}, "quality":{"qxl":0,"kkx":0},"meanNum":{"qxl":0,"kkx":0},"variance":{"qxl":0,"kkx":0} }
这时候如果改变数据格式为列表中的无嵌套字典格式比较麻烦,可以自定义过滤器来获取数据,
from django.template.defaulttags import register @register.filter def getArgQxlValue(dictionary,arg): return dictionary[arg]['qxl'] @register.filter def getArgKkxValue(dictionary,arg): return dictionary[arg]['kkx'] @register.filter def getArgName(dictionary,arg): return dictionary[arg]['name']
在模板中就可以以这样写
<!-- the second important page of the project--> {% load staticfiles %} <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>超标信息</title> <script src="{% static 'js/a-mynewjs.js' %}"></script> </head> <body> {{ guestSetArgs|safe }}<br><br><br> {{ warningdata|safe }}<br><br> <script> {% for i in guestSetArgs %} {% for j in warningdata %} if("{{i}}"=="{{j}}") { if(Number({{warningdata|getArgQxlValue:j}})>Number({{guestSetArgs|getArgQxlValue:i}})) var setArgStr="{{warningdata|getArgName:i}} 超出阀值 阀值:{{guestSetArgs|getArgQxlValue:j}} 检测值:{{warningdata|getArgQxlValue:j}}<br>" document.write(setArgStr); } {% endfor %} {% endfor %} </script> </body> </html>
形如{{warningdata|getArgQxlValue:j}},就可以获取到里面的值了
参考自https://docs.djangoproject.com/en/2.2/howto/custom-template-tags/
作者:好难受
链接:https://www.pythonheidong.com/blog/article/18648/e15d84afb17f150a7239/
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