How do I fix my closed form mathematical formula that returns 0 or 1 only whether or not theformula is true or false?
发布于2024-12-08 09:46 阅读(827) 评论(0) 点赞(19) 收藏(4)
I need help with my mathematical formula in python. I want to fix it because it's returning -1 for some values and it's not properly returning 0 and 1 when n is the right number.
All I'm trying to do is create a mathematical formula I can use in python (only addition and subtraction) that can tell when the formula (n % 3) is 0. Based on the value of n it will return 0 if the answer isn't 0 or 1 if it's 0.
My code is:
n = 10
result = 1 - ((n % 3) + ((n % 3) - 1) + ((n % 3) - 2))
print(result)
The result should return 1 and 0 depending on if it's true or not so I can use this code properly.
解决方案
The issue with your formula is that its overly complex and does not correctly implement the logic you want that is: returning 1ifn % 3 == 0 and 0 otherwise.
Simplest approach if you are okay using conditional expressions in python, this is the easiest solution:
n = 10
result = 1 if n % 3 == 0 else 0
print(result)
所属网站分类: 技术文章 > 问答
作者：黑洞官方问答小能手
链接：https://www.pythonheidong.com/blog/article/2046414/1439f77125847512b179/
来源：python黑洞网
任何形式的转载都请注明出处,如有侵权 一经发现 必将追究其法律责任
昵称:
评论内容：(最多支持255个字符)
---无人问津也好，技不如人也罢，你都要试着安静下来，去做自己该做的事，而不是让内心的烦躁、焦虑，坏掉你本来就不多的热情和定力