发布于2025-01-05 09:01 阅读(448) 评论(0) 点赞(28) 收藏(5)
This is mainly framed towards Numpy arrays but I feel it's a general design problem. In many cases I have the following generic problem in scientific computing: I have to read a dataset composed of several time instances of a certain vector field, e.g. the time-varying velocity field on a number of points. Something that could be a 3D array of sizes (Npoints, 3, Ntimesteps)
(3 because I have three components of a vector). I normally would have one file per timestep, so I'd have to read Ntimesteps
files, but I don't know beforehand the size of each field (i.e. I don't know Npoints
beforehand, but it's the same for each file). If I want to preallocate the Numpy array to store this data, I got used to doing something along these lines:
tsteps = list(glob.glob('time*.csv'))
Nsteps = len(tsteps)
with open(tsteps[0], 'r') as f:
# do my work to get Npoints and the data of the first file
dataset = np.zeros(Npoints, 3, Nsteps)
dataset[:,:,0] = data_first_file
for i,f in enumerate(tsteps[1:]):
# do my work again
dataset[:,:,i] = data_from_tstep_i
However, this does not look very 'elegant' since I have to write twice the code to process each timestep file: once to preallocate the array and once in the loop. Is there a more elegant pattern to do this?
i think that there's no elegant way to do it if you don't know the shape in advance. but you should initiate it inside the loop for readability
tsteps = glob.glob('time*.csv')
for i, filename in enumerate(tsteps):
with open(filename) as f:
data_i = np.loadtxt(f)
if i==0:
dataset = np.zeros(data_i.shape[0], 3, len(tsteps))
dataset[:,:,i] = data_i
作者:黑洞官方问答小能手
链接:https://www.pythonheidong.com/blog/article/2046774/7ac30966d2498053fae3/
来源:python黑洞网
任何形式的转载都请注明出处,如有侵权 一经发现 必将追究其法律责任
昵称:
评论内容:(最多支持255个字符)
---无人问津也好,技不如人也罢,你都要试着安静下来,去做自己该做的事,而不是让内心的烦躁、焦虑,坏掉你本来就不多的热情和定力
Copyright © 2018-2021 python黑洞网 All Rights Reserved 版权所有,并保留所有权利。 京ICP备18063182号-1
投诉与举报,广告合作请联系vgs_info@163.com或QQ3083709327
免责声明:网站文章均由用户上传,仅供读者学习交流使用,禁止用做商业用途。若文章涉及色情,反动,侵权等违法信息,请向我们举报,一经核实我们会立即删除!