发布于2019-08-17 21:45 阅读(1054) 评论(0) 点赞(5) 收藏(0)
- import datetime
-
- def find_close(arr, e):
- start_time = datetime.datetime.now()
-
- size = len(arr)
- idx = 0
- val = abs(e - arr[idx])
-
- for i in range(1, size):
- val1 = abs(e - arr[i])
- if val1 < val:
- idx = i
- val = val1
-
- use_time = datetime.datetime.now() - start_time
-
- return arr[idx], use_time.seconds * 1000 + use_time.microseconds / 1000
-
- def find_close_fast(arr, e):
- start_time = datetime.datetime.now()
-
- low = 0
- high = len(arr) - 1
- idx = -1
-
- while low <= high:
- mid = int((low + high) / 2)
- if e == arr[mid] or mid == low:
- idx = mid
- break
- elif e > arr[mid]:
- low = mid
- elif e < arr[mid]:
- high = mid
-
- if idx + 1 < len(arr) and abs(e - arr[idx]) > abs(e - arr[idx + 1]):
- idx += 1
-
- use_time = datetime.datetime.now() - start_time
-
- return arr[idx], use_time.seconds * 1000 + use_time.microseconds / 1000
-
- if __name__ == "__main__":
- arr = []
-
- f = open("1Mints.txt")
- for line in f:
- arr.append(int(line))
- f.close()
-
- arr.sort()
-
- while 1:
- e = int(input("input a number:"))
- print("find_close ", find_close(arr, e))
- print ("find_close_fast ", find_close_fast(arr, e))
作者:搞笑
链接:https://www.pythonheidong.com/blog/article/48513/98b68c8071ea6914d863/
来源:python黑洞网
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